-16x^2+192x+1728=0

Solution for -16x^2+192x+1728=0 equation:

-16x^2+192x+1728=0

a = -16; b = 192; c = +1728;
Δ = b2-4ac
Δ = 1922-4·(-16)·1728
Δ = 147456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{147456}=384$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(192)-384}{2*-16}=\frac{-576}{-32}
=+18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(192)+384}{2*-16}=\frac{192}{-32}
=-6
$